Physical Science

SolutionsQ mcoWhere Q quantity of heatm massc specific heat capacityo change in temperatureIfm 30g , c 0 .055cal (g0C , and o 750CThenQ 30g x 0 .055cal (g0C ) x 750CQ 123 .75calSince1 cal 4 .184 joules123 .75cal 123 .75 x 4 .184 joulesQ 517 .77 joules2 If average kinetic energy (K .E (3 /2 ) KT and K 1 .38 x 10-23 J / mite KWhen T 300KK .E 3 /2 x 1 .38 x 10-23J / pinpoint K x 300KK .E 6 .21 x 10-21J /moleculeBut , K .E 1 /2mv2 6 .21 x 10-21JWhere m mass , v velocity6 .022 x 1023 O2 molecules weigh 31 .9988g1 molecule of O2 molecule would weigh 31 .9988g /6 .022 x 1023 5 .31365 x 10-23gConverting to kg 5 .314 x 10-26kgSubstituting into 1 /2mv2 ?2 .34 x 105kgm2 /s2 /kg (joule kgm2 /s2v 483 .

74m /s3 dissolve point of Silver (m .p 960 .80Cm .p . in Kelvin (960 .8 273 ) K 1233 .8Km .p . in Fahrenheit 90C /5 32 9 x 960 .80C /5 32 1761 .440F4 The use of the absolute temperature scale is justified by the existence of absolute zero temperature . The scale thus assumes an upper limit of 373 .15K and 273 .15K as minimum temperature for existence of gas temperatureOn the crooked part , gasses cease to exist , in theory , at the absolute zero...If you want to get a full essay, absorb it on our website: BestEssayCheap.com

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